Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
488 views
in Technique[技术] by (71.8m points)

hex - java- how to generate a random hexadecimal value within specified range of values

I have a scenario in a java web app, where a random hexadecimal value has to be generated. This value should be within a range of values specified by me. (The range of values can be hexadecimal or integer values).

What is the most efficient way to do this> Do I have to generate a random decimal number, and then convert it to hexadecimal? Or can a value be directly generated?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Yes, you just generate a decimal value in your range. Something such as:

Random rand = new Random();
int myRandomNumber = rand.nextInt(0x10) + 0x10; // Generates a random number between 0x10 and 0x20
System.out.printf("%x
",myRandomNumber); // Prints it in hex, such as "0x14"
// or....
String result = Integer.toHexString(myRandomNumber); // Random hex number in result

Hex and decimal numbers are handled the same way in Java (as integers), and are just displayed or inputted differently. (More info on that.)


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...