Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
974 views
in Technique[技术] by (71.8m points)

git submodule foreach - Robust way to recursively commit a child module first?

Is there a robust way to do a recursive depth-first git submodule foreach command? I am using the foreach --recursive command which does the job, except it is breadth-first. This is a problem because if I have the following structure:

  • A
    • B
  • C

And I have commits in all three, a foreach --recursive add -A && git commit ... will hit A, B, C, which is problematic if I want the supermodule to capture the commits of B at that time.

I found this discussion from 2008, but it does not look like any of the suggested features are in the current version of Git that I have (1.7.9.5).

I wrote a small bash function to do this (excuse the shorthand naming):

function git-sfed() { git submodule foreach "git submodule foreach '$*' && $*"; }

And testing it with the following fanciful command seems to work:

git-sfed 'python -c "import sys; print sys.argv" $path'

Does this command seem robust, or are there other common existing methods?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can try this

git submodule  foreach --recursive  |  tail  -r | sed 's/Entering//' | xargs -I% cd % ; git add -A & git commit

This list (recursively) all the submodules , then reverse the list, tail -r so you get the directories in the order you want (child first), enter the directory and do what ever you want in it.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...