Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
906 views
in Technique[技术] by (71.8m points)

ffmpeg av_read_frame() need very long time to stop

I use ffmpeg to decode RTSP video.It likes that: When it's on the end of file,it block in the av_read_frame() for a long time,why?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Various reasons can cause long blocking. But you can control the processing time for a I/O layer.

Use the structure AVFormatContext::interrupt_callback to set the interrupt handler.

class timeout_handler {
  public:
    timeout_handler(unsigned int t) : timeout_ms_(TimeoutMs){}

    void reset(unsigned int 0) {
      timeout_ms_ = TimeoutMs;
      lastTime_ = my_get_local_time();
    }

    bool is_timeout(){
      const my_time_duration actualDelay = my_get_local_time() - lastTime_;
      return actualDelay > timeout_ms_;
    }

    static int check_interrupt(void * t) {
       return t && static_cast<timeout_handler *>(t)->is_timeout();
    }

 public:
   unsigned int timeout_ms_;
   my_time_t lastTime_;      
 };


 /// .................
 AVFormatContext * ic;
 timeout_handler * th = new timeout_handler(kDefaultTimeout);
 /// .................
 ic->interrupt_callback.opaque = (void*)th ;
 ic->interrupt_callback.callback = &timeout_handler::check_interrupt;
 /// open input
 // avformat_open_input(ic, ... );
 // etc

 /// .................
 /// before any I/O operations, for example:
 th->reset(kDefaultTimeout);
 int e = AVERROR(EAGAIN);
 while (AVERROR(EAGAIN) == e) 
  e = av_read_frame(ic, &packet);
 // If the time exceeds the limit, then the process interruped at the next IO operation.   

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...