python - Getting all the min elements and its indices from a list

Question

I have a list that has a minimum element that is present multiple times like

a = [1,2,1,1,4,5,6]

And I want Python to return the element 1 and all the indices in the list where 1 is present. I tried using

min_index, min_value = min(enumerate(a), key=operator.itemgetter(1))

which gives only the index where 1 occurs first.

Answer 1

I'd just do it like this:

minimum = min(a)
indices = [i for i, v in enumerate(a) if v == minimum]