Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
593 views
in Technique[技术] by (71.8m points)

r - Percentage of overlap between polygons

I'm new to R and it's my first time posting here, thought to let you guys know I'm still a newbie in the R language with the hope it will simplify your answers. I'm currently doing my masters dissertation which includes a lot of work with shapefiles containing distributions of different species in South Africa. My research includes 4 families of animals; 1 prey family (consisting of 29 species) and 3 predatory families (each containing even more species). For each species I have a shapefile with a polygon of their distribution, so I have a LOT of shapefiles. My problem now is, I have to calculate the percentage of overlap each predator has with each prey species (100% overlap is when the distribution/polygon of the predator is within the distribution/polygon of the prey, so percentage should be calculated relative to the polygon of the prey species).

I know I could probably do this one by one for each species separately, but this would literally take me weeks and I don't have time for that. Even my promotor at uni hasn't done anything like this before and is trying to figure it out himself. He originally gave me this code:

my_rangemaps <- list.files(path = "imagine_rangemaps", pattern = ".shp", full.names = TRUE) 
my_rangemaps 
rangemap_matrix <- pairwiseRangemaps(my_rangemaps, projection = 3035, 
             Ncpu = 1, nchunks = 1, filename = "rangemap_matrix.csv") 

But the result was not what we expected as it doesn't calculate percentages relative to whatever polygon. Does anyone know a way to get percentages of overlap using a relative easy code without too much fuzz? Maybe resulting in the form of a matrix containing all species/shapefiles/polygons?

Thank you all in advance!

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

For the fun of it, here's an example. Some folks here or on gis.stackexchange.com might have better ways in petto:

library(raster)
library(sp)
## example data:
p1 <- structure(c(0, 0, 0.4, 0.4, 0, 0.6, 0.6, 0), .Dim = c(4L, 2L), .Dimnames = list(NULL, c("x", "y")))
p2 <- structure(c(0.2, 0.2, 0.6, 0.6, 0, 0.4, 0.4, 0), .Dim = c(4L, 2L), .Dimnames = list(NULL, c("x", "y")))
p3 <- structure(c(0, 0, 0.8, 0.8, 0, 0.8, 0.8, 0), .Dim = c(4L, 2L), .Dimnames = list(NULL, c("x", "y")))
poly <- SpatialPolygons(list(Polygons(list(Polygon(p1)), "a"),Polygons(list(Polygon(p2)), "b"),Polygons(list(Polygon(p3)), "c")),1L:3L)
plot(poly)

enter image description here

## areas for the original shapes:
areas_poly <- vector(length = length(poly)) 
for (x in seq_along(poly)) areas_poly[x]<-area(poly[x])

## areas for the overlapping regions:
idx <- combn(seq_along(poly),2)
areas_intersect <- sapply(1:ncol(idx), function(x) {
  area(intersect(poly[idx[1,x]], poly[idx[2,x]])) 
})

## get overlaps in percentages:
overlap_perc <- 
  round(do.call(cbind, lapply(seq_len(ncol(idx)), function(x)  
  rbind(
    areas_intersect[x] / areas_poly[idx[1,x]] * 100, 
    areas_intersect[x] / areas_poly[idx[2,x]] * 100
  )
)), 2)

## into matrix form:
m <- matrix(100, ncol=length(poly), nrow=length(poly))
m[rbind(t(idx),t(idx)[,2:1])] <- as.vector(t(overlap_perc))
m
#       [,1]   [,2] [,3]
# [1,] 100.0  33.33  100
# [2,]  50.0 100.00  100
# [3,]  37.5  25.00  100

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...