Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
368 views
in Technique[技术] by (71.8m points)

window - Android 4.2 ACTION_OUTSIDE MotionEvent X and Y return 0 outside of own application

I created a TYPE_SYSTEM_ALERT view, set the flags FLAG_NOT_TOUCH_MODAL and FLAG_WATCH_OUTSIDE_TOUCH, and added it with WindowManager.addView().

When I touch outside of the view onto my own activity, everything works and MotionEvent.getY() returns the correct value.

However, if I exit my activity and and touch onto another application, MotionEvent.getY() always returns 0.

I'm not sure if this only happens on 4.2 or not.

Any help would be appreciated!

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

It's unfortunate that this question has remained unanswered for 1.5 years, but I ran into the same thing you did and found out why!

After scouring the source code, I found the source of the issue:

https://github.com/android/platform_frameworks_base/blob/79e0206ef3203a1842949242e58fa8f3c25eb129/services/input/InputDispatcher.cpp#L1417

// Check whether windows listening for outside touches are owned by the same UID. If it is
// set the policy flag that we will not reveal coordinate information to this window.
if (maskedAction == AMOTION_EVENT_ACTION_DOWN) {
    sp<InputWindowHandle> foregroundWindowHandle =
            mTempTouchState.getFirstForegroundWindowHandle();
    const int32_t foregroundWindowUid = foregroundWindowHandle->getInfo()->ownerUid;
    for (size_t i = 0; i < mTempTouchState.windows.size(); i++) {
        const TouchedWindow& touchedWindow = mTempTouchState.windows[i];
        if (touchedWindow.targetFlags & InputTarget::FLAG_DISPATCH_AS_OUTSIDE) {
            sp<InputWindowHandle> inputWindowHandle = touchedWindow.windowHandle;
            if (inputWindowHandle->getInfo()->ownerUid != foregroundWindowUid) {
                mTempTouchState.addOrUpdateWindow(inputWindowHandle,
                        InputTarget::FLAG_ZERO_COORDS, BitSet32(0));
            }
        }
    }
}

If the "outside touch" lands in a view that doesn't share its UID (read about it here) with the view that's listening for outside touches, the event dispatcher sets its coordinates to 0,0. This was definitely done for security purposes, but I'm not sure I see the full scope of the threat it's designed to mitigate. And this gentleman here (SO) reports that you can retrieve location data on 2.3.6, but it seems that at least 4.x won't reveal it to you (I tried 4.1.2, it didn't work).

I opened up a bug ticket about this if you'd like to follow it. At the very least, the documentation needs to include this information... I would also like to know if this security feature is really necessary.

Issue 72746: FLAG_WATCH_OUTSIDE_TOUCH doesn't return location for ACTION_OUTSIDE events on 4.2+


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...