Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
816 views
in Technique[技术] by (71.8m points)

php - Warning while using file_get_contents for google api

I am using this code for finding the lat lon of a location

$api='http://maps.googleapis.com/maps/api/geocode/json?address=United States Neversink&sensor=false';

$result = file_get_contents($api);

$data = json_decode($result);

But it give the warning Warning: file_get_contents(http://maps.googleapis.com/maps/api/geocode/json?address=United States Neversink&sensor=false) [function.file-get-contents]: failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request in C:wampwww ew_yellowpagesmodulesmod_yellowpages_item_maphelper.php on line 139

if anyone know about this problem help me please.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Use curl instead of file_get_contents:

$address = "India+Panchkula";
$url = "http://maps.google.com/maps/api/geocode/json?address=$address&sensor=false&region=India";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_PROXYPORT, 3128);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
$response = curl_exec($ch);
curl_close($ch);
$response_a = json_decode($response);
echo $lat = $response_a->results[0]->geometry->location->lat;
echo "<br />";
echo $long = $response_a->results[0]->geometry->location->lng;

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...