Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
334 views
in Technique[技术] by (71.8m points)

inversion of control - Does Castle-Windsor support ForwardedTypes via XML configuration

I have a class that implements multiple interfaces. I would like to register these interfaces via XML. All I've found is documentation for the new Fluent Interface. Is this option supported via XML? What would be involved in adding this feature?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

[Update] This is now possible in Windsor 2.1 or newer. See the documentation for syntax here.


This feature has not been implemented in the XML interpreter as of yet.. however it is not difficult to add support for it via a facility (obviously this technique is also useful when wanting to add other features absent from the existing configuration parser).

So first off we add a facility which will detect when a handler is created for a type, and at the same time will register any of the forwarded services so they point to the existing handler:

public class HandlerForwardingFacility : AbstractFacility
{
  IConversionManager conversionManager;

  protected override void Init()
  {
    conversionManager = (IConversionManager)Kernel.GetSubSystem(SubSystemConstants.ConversionManagerKey);
    Kernel.HandlerRegistered += new HandlerDelegate(Kernel_HandlerRegistered);      
  }

  void Kernel_HandlerRegistered(IHandler handler, ref bool stateChanged)
  {
    if (handler is ForwardingHandler) return;

    var model = handler.ComponentModel;

    if (model.Configuration == null) return;

    var forward = model.Configuration.Children["forward"];
    if (forward == null) return;

    foreach (var service in forward.Children)
    {
      Type forwardedType = (Type)conversionManager.PerformConversion(service, typeof (Type));
      Kernel.RegisterHandlerForwarding(forwardedType, model.Name);
    }
  }
}

And then of course we need to make use of this in code, for this example I'm going to have a mutant duck/dog component that supports two separate services - IDuck and IDog:

public interface IDog
{
  void Bark();
}

public interface IDuck
{
  void Quack();
}

public class Mutant : IDog, IDuck
{
  public void Bark()
  {
    Console.WriteLine("Bark");
  }

  public void Quack()
  {
    Console.WriteLine("Quack");
  }
}

Now to actually configure the container:

 <castle>
  <facilities>
    <facility id="facility.handlerForwarding" type="Example.Facilities.HandlerForwardingFacility, Example" />
  </facilities>
  <components>
    <component id="mutant" service="Example.IDog, Example" type="Example.Mutant, Example">
      <forward>
        <service>Example.IDuck, Example</service>
      </forward>
    </component>
  </components>
</castle>

And now we can happily execute a test like this:

  WindsorContainer container = new WindsorContainer(new XmlInterpreter());

  var dog = container.Resolve<IDog>();
  var duck = container.Resolve<IDuck>();

  Assert.AreSame(dog, duck);

Hope this helps.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...