Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
608 views
in Technique[技术] by (71.8m points)

floating point - How does R represent NA internally?

R seems to support an efficient NA value in floating point arrays. How does it represent it internally?

My (perhaps flawed) understanding is that modern CPUs can carry out floating point calculations in hardware, including efficient handling of Inf, -Inf and NaN values. How does NA fit into this, and how is it implemented without compromising performance?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

R uses NaN values as defined for IEEE floats to represent NA_real_, Inf and NA. We can use a simple C++ function to make this explicit:

Rcpp::cppFunction('void print_hex(double x) {
    uint64_t y;
    static_assert(sizeof x == sizeof y, "Size does not match!");
    std::memcpy(&y, &x, sizeof y);
    Rcpp::Rcout << std::hex << y << std::endl;
}', plugins = "cpp11", includes = "#include <cstdint>")
print_hex(NA_real_)
#> 7ff80000000007a2
print_hex(Inf)
#> 7ff0000000000000
print_hex(-Inf)
#> fff0000000000000

The exponent (second till 13. bit) is all one. This is the definition of an IEEE NaN. But while for Inf the mantissa is all zero, this is not the case for NA_real_. Here some source code references.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...