Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
784 views
in Technique[技术] by (71.8m points)

numpy - How to declare 2D c-arrays dynamically in Cython

I need to perform a lot of work using 2D numpy arrays of various sizes and I would like to offload these calculations onto cython. The idea is that my 2D numpy arrays would be passed from python to cython where it would be converted into c-array or memory view and used in a cascade of other c-level functions to do the calculations.

After some profiling I ruled out using numpy arrays in cython due to some serious python overhead. Using memory views was MUCH faster and quite easy to use, but I suspect I can squeeze even more speedup from using c-arrays.

Here is my question though - how can I declare a 2D c-array in cython without predefining its dimensions with set values? For example, I can create a c-array from numpy this way:

narr = np.array([[1,2,3,4],[5,6,7,8],[9,10,11,12]], dtype=np.dtype("i"))

cdef int c_arr[3][4]:
for i in range(3):
    for j in range(4):
        c_arr[i][j] = narr[i][j]

and then pass it to a function:

cdef void somefunction(int c_Arr[3][4]):
    ...

But this implies I have a fixed sizde of array, which in my case will be useless. So I tried something like this:

narr = np.array([[1,2,3,4],[5,6,7,8],[9,10,11,12]], dtype=np.dtype("i"))

cdef int a = np.shape(narr)[0]
cdef int b = np.shape(narr)[1]

cdef int c_arr[a][b]:               # INCORRECT - EXAMPLE ONLY

for i in range(a):
    for j in range(b):
        c_arr[i][j] = narr[i][j]

with the intention to pass it to a function like this:

cdef void somefunction(int a, int b, int c_Arr[a][b]):
    ...

But it doesn't work and the compilation fails with the error "Not allowed in a constant expression". I suspect I need t do it with malloc/free somehow? I had a look at this problem (How to declare 2D list in Cython), but it does not provide the answer to my problem.

UPDATE:

It turns out that memory-views can be as fast as c-arrays if one makes sure that indexError checking in cython is switched-off for the memory views, which can be done by using cython compiler directive:

# cython: boundscheck=False

Thanks @Veedrac for the tip!

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You just need to stop doing bounds checking:

with cython.boundscheck(False):
    thesum += x_view[i,j]

that brings the speed basically up to par.


If you really want a C array from it, try:

import numpy as numpy
from numpy import int32
from numpy cimport int32_t

numpy_array = numpy.array([[]], dtype=int32)

cdef:
    int32_t[:, :] cython_view = numpy_array
    int32_t *c_integers_array = &cython_view[0, 0]
    int32_t[4] *c_2d_array = <int32_t[4] *>c_integers_array

First you get a Numpy array. You use that to get a memory view. Then you get a pointer to its data, which you cast to pointers of the desired stride.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...