Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
499 views
in Technique[技术] by (71.8m points)

javascript - reversed Y-axis D3

I created a bar plot and my Y axis is reversed somehow (also seems like the scale is not right). I really couldn't figure it out by myself. Here is the link for Jsfiddle.

This is the code I am working on, in case you want to try it elsewhere.

var w = 700;
var h = 400;
var margin = 40;

var dataset = [
{key:1,value:4000},
{key:2,value:3500},
{key:3,value:4400},
{key:4,value:3250},
{key:5,value:4785},
{key:6,value:3600},
{key:7,value:3200}
];


var key = function(d) {
    return d.key;
};

var value = function(d) {
    return d.value;
};
console.log(dataset);

//Create SVG element
var svg = d3.select("body")
            .append("svg")
            .attr("width", w)
            .attr("height", h);

var xScale = d3.scale.ordinal()
                .domain(d3.range(dataset.length+1))
                .rangeRoundBands([40, w], 0.05); 

var yScale = d3.scale.linear()
                     .domain([0, 5000])
                     .range([0, h-40]);
                
var x_axis = d3.svg.axis().scale(xScale);
var y_axis = d3.svg.axis().scale(yScale).orient("left");


d3.select("svg")
    .append("g")
        .attr("class","x axis")
        .attr("transform","translate(0,"+(h-margin)+")")
    .call(x_axis);
        
d3.select("svg")
    .append("g")
        .attr("class","y axis")
        .attr("transform","translate("+margin+",0)")
    .call(y_axis);
    
//Create bars
svg.selectAll("rect")
   .data(dataset, key)
   .enter()
   .append("rect")
   .attr("x", function(d, i) {
        return xScale(i);
   })
   .attr("y", function(d) {
        return h - yScale(d.value);
   })
   .attr("width", xScale.rangeBand())
   .attr("height", function(d) {
        return yScale(d.value)-margin;
   })
   .attr("fill", function(d) {
        return "rgb(96, 0, " + (d.value * 10) + ")";
   })

    //Tooltip
.on("mouseover", function(d) {
    //Get this bar's x/y values, then augment for the tooltip
    var xPosition = parseFloat(d3.select(this).attr("x")) + xScale.rangeBand() / 2;
    var yPosition = parseFloat(d3.select(this).attr("y")) + 14;
    
    //Update Tooltip Position & value
    d3.select("#tooltip")
        .style("left", xPosition + "px")
        .style("top", yPosition + "px")
        .select("#value")
        .text(d.value);
    d3.select("#tooltip").classed("hidden", false)
})
.on("mouseout", function() {
    //Remove the tooltip
    d3.select("#tooltip").classed("hidden", true);
})  ;

//Create labels
svg.selectAll("text")
   .data(dataset, key)
   .enter()
   .append("text")
   .text(function(d) {
        return d.value;
   })
   .attr("text-anchor", "middle")
   .attr("x", function(d, i) {
        return xScale(i) + xScale.rangeBand() / 2;
   })
   .attr("y", function(d) {
        return h - yScale(d.value) + 14;
   })
   .attr("font-family", "sans-serif") 
   .attr("font-size", "11px")
   .attr("fill", "white");
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Maybe this will help.

http://jsfiddle.net/S575k/4/

A few notes:

  1. I reversed your y domain range from .range([0, h-margin]); to .range([h-margin, 0]); This will fix the issue of the y-axis marks going in the wrong direction because the browser consider's the origin (0,0) point to the the upper-left corner, and not the bottom-left corner like in math.

  2. Because of this reversal I had to tweak your .attr('height') and .attr('y').

  3. A nice way to find the height of bar in a bar chart is to realize that the yscale(0) will give you the pixel-position of the bottom of the barchart. You can then do yscale(value) - yscale(0) to get the pixel-height of your bars.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...