Python : How to stop while loop while sorting list?

Question

I am writing code to sort elements in list and I kind of achieved it but unable to stop while loop.

I want to stop while loop when all element in list are sorted.

Code:

a = [27,21,22,1,11,23,0]
n=len(a)
while True:
    for i in range(n-1):
        if a[i]>a[i+1]:
            temp = a[i]
            a[i] = a[i+1]
            a[i+1] = temp
    print(a)

Output:

[21, 22, 1, 11, 23, 0, 27] [21, 1, 11, 22, 0, 23, 27] [1, 11, 21, 0, 22, 23, 27] [1, 11, 0, 21, 22, 23, 27] [1, 0, 11, 21, 22, 23, 27] [0, 1, 11, 21, 22, 23, 27] [0, 1, 11, 21, 22, 23, 27] [0, 1, 11, 21, 22, 23, 27] [0, 1, 11, 21, 22, 23, 27]........

I know there are 10s of Q&A on sorting list but I want to achieve this way only(if possible).

Can anyone help me to stop this while loop?

Answer 1

Perhaps a bit more efficient than chepner's, not having an extra assignment for every swap, instead just use temp to detect whether there was a change:

a = [27,21,22,1,11,23,0]
n = len(a)
dummy = object()
while True:
    temp = dummy
    for i in range(n-1):
        if a[i]>a[i+1]:
            temp = a[i]
            a[i] = a[i+1]
            a[i+1] = temp
    if temp is dummy:
        break
    print(a)