Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
564 views
in Technique[技术] by (71.8m points)

r - How to use data.table to efficiently calculate allele frequencies (proportions) by group across multiple columns (loci)

I have a data.table of allele identities (rows are individuals, columns are loci), grouped by a separate column. I want to calculate allele frequencies (proportions) for each locus efficiently, by group. An example data table:

    DT = data.table(Loc1=rep(c("G","T"),each=5), 
      Loc2=c("C","A"), Loc3=c("C","G","G","G",
      "C","G","G","G","G","G"), 
    Group=c(rep("G1",3),rep("G2",4),rep("G3",3)))
    for(i in 1:3)
        set(DT, sample(10,2), i, NA)
    > DT
        Loc1 Loc2 Loc3 Group
     1:    G   NA    C    G1
     2:    G    A    G    G1
     3:    G    C    G    G1
     4:   NA   NA   NA    G2
     5:    G    C   NA    G2
     6:    T    A    G    G2
     7:    T    C    G    G2
     8:    T    A    G    G3
     9:    T    C    G    G3
    10:   NA    A    G    G3

The problem I have is that when I try to do calculations by group, only the allele i.d.s present in the group are recognized, so I'm struggling to find code that can tell me e.g. the proportion of G's for locus 1 in all 3 groups. Simple example, calculating a sum (not proportion) for the first allele at each locus:

    > fun1<- function(x){sum(na.omit(x==unique(na.omit(x))[1]))}
    > DT[,lapply(.SD,fun1),by=Group,.SDcols=1:3]
       Group Loc1 Loc2 Loc3
    1:    G1    3    1    1
    2:    G2    1    2    2
    3:    G3    2    2    3

For G1 the result is that Loc1 has 3 G's, but for G3 it shows Loc1 has 2 T's, not the number of G's. I want the number of G's for both in this case. So the key problem is that the allele identities are determined by group, not over the whole column. I tried making a separate table with the allele identities I want to use in calculations, but can't figure out how to include it in fun1 so that the correct cells are referenced in lapply above. Allele identities table:

    > fun2<- function(x){sort(na.omit(unique(x)))}
    > allele.id<-data.table(DT[,lapply(.SD,fun2),.SDcols=1:3])
    > allele.id
       Loc1 Loc2 Loc3
    1:    G    A    C
    2:    T    C    G
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

It's probably wise to transform your data.table into long format first. This will make it easier to use for further calculations (or making visualisations with ggplot2 for example). With the melt function of data.table (which works the same as the melt function of the reshape2 package) you can transform from wide to long format:

DT2 <- melt(DT, id = "Group", variable.name = "loci")

When you want to remove the NA-values during the melt-operation, you can add na.rm = TRUE in the above call (na.rm = FALSE is the default behaviour).

Then you can make count and proportion variables as follows:

DT2 <- DT2[, .N, by = .(Group, loci, value)][, prop := N/sum(N), by = .(Group, loci)]

which gives the following result:

> DT2
    Group loci value N      prop
 1:    G1 Loc1     G 3 1.0000000
 2:    G2 Loc1    NA 1 0.2500000
 3:    G2 Loc1     G 1 0.2500000
 4:    G2 Loc1     T 2 0.5000000
 5:    G3 Loc1     T 2 0.6666667
 6:    G3 Loc1    NA 1 0.3333333
 7:    G1 Loc2    NA 1 0.3333333
 8:    G1 Loc2     A 1 0.3333333
 9:    G1 Loc2     C 1 0.3333333
10:    G2 Loc2    NA 1 0.2500000
11:    G2 Loc2     C 2 0.5000000
12:    G2 Loc2     A 1 0.2500000
13:    G3 Loc2     A 2 0.6666667
14:    G3 Loc2     C 1 0.3333333
15:    G1 Loc3     C 1 0.3333333
16:    G1 Loc3     G 2 0.6666667
17:    G2 Loc3    NA 2 0.5000000
18:    G2 Loc3     G 2 0.5000000
19:    G3 Loc3     G 3 1.0000000

I you want it back in wide format, you can use dcast on multiple variables:

DT3 <- dcast(DT2, Group + loci ~ value, value.var = c("N", "prop"), fill = 0)

which results in:

> DT3
   Group loci N_A N_C N_G N_T N_NA    prop_A    prop_C    prop_G    prop_T   prop_NA
1:    G1 Loc1   0   0   3   0    0 0.0000000 0.0000000 1.0000000 0.0000000 0.0000000
2:    G1 Loc2   1   1   0   0    1 0.3333333 0.3333333 0.0000000 0.0000000 0.3333333
3:    G1 Loc3   0   1   2   0    0 0.0000000 0.3333333 0.6666667 0.0000000 0.0000000
4:    G2 Loc1   0   0   1   2    1 0.0000000 0.0000000 0.2500000 0.5000000 0.2500000
5:    G2 Loc2   1   2   0   0    1 0.2500000 0.5000000 0.0000000 0.0000000 0.2500000
6:    G2 Loc3   0   0   2   0    2 0.0000000 0.0000000 0.5000000 0.0000000 0.5000000
7:    G3 Loc1   0   0   0   2    1 0.0000000 0.0000000 0.0000000 0.6666667 0.3333333
8:    G3 Loc2   2   1   0   0    0 0.6666667 0.3333333 0.0000000 0.0000000 0.0000000
9:    G3 Loc3   0   0   3   0    0 0.0000000 0.0000000 1.0000000 0.0000000 0.0000000

Another and straightforward approach is using melt and dcast in one call (which is a simplified version of the first part of @Frank's answer):

DT2 <- dcast(melt(DT, id="Group"), Group + variable ~ value)

which gives:

> DT2
   Group variable A C G T NA
1:    G1     Loc1 0 0 3 0  0
2:    G1     Loc2 1 1 0 0  1
3:    G1     Loc3 0 1 2 0  0
4:    G2     Loc1 0 0 1 2  1
5:    G2     Loc2 1 2 0 0  1
6:    G2     Loc3 0 0 2 0  2
7:    G3     Loc1 0 0 0 2  1
8:    G3     Loc2 2 1 0 0  0
9:    G3     Loc3 0 0 3 0  0

Because the default aggregation function in dcast is length, you will automatically get the counts for each of the values.


Used data:

DT <- structure(list(Loc1 = c("G", "G", "G", NA, "G", "T", "T", "T", "T", NA), 
                     Loc2 = c(NA, "A", "C", NA, "C", "A", "C", "A", "C", "A"), 
                     Loc3 = c("C", "G", "G", NA, NA, "G", "G", "G", "G", "G"), 
                     Group = c("G1", "G1", "G1", "G2", "G2", "G2", "G2", "G3", "G3", "G3")), 
                .Names = c("Loc1", "Loc2", "Loc3", "Group"), row.names = c(NA, -10L), class = c("data.table", "data.frame"))

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...