Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
543 views
in Technique[技术] by (71.8m points)

jpeg - Java ARGB to JPG

How can I save BufferedImage with TYPE_INT_ARGB to jpg?

Program generates me that image:

enter image description here

And it's OK, but when I save it in that way:

    ByteArrayOutputStream byteStream = new ByteArrayOutputStream();
    BufferedOutputStream bos = new BufferedOutputStream(byteStream);
    try {
        ImageIO.write(buffImg, "jpg", bos);
        // argb
        byteStream.flush();
        byte[] newImage = byteStream.toByteArray();

        OutputStream out = new BufferedOutputStream(new FileOutputStream("D:\test.jpg"));
        out.write(newImage);
        out.close();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

The result is: enter image description here

Understand that this is due to the alpha layer, but don't know how to fix it. Png format does not suit me, need jpg.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

OK! I've solved it. Everything was pretty easy. Don't know is it a good decision and how fast it is. I have not found any other. So.. everything we need is define new BufferedImage.

BufferedImage buffImg = new BufferedImage(getWidth(), getHeight(), BufferedImage.TYPE_INT_ARGB);
Graphics2D g2 = buffImg.createGraphics();

// ... other code we need

BufferedImage img= new BufferedImage(buffImg.getWidth(), buffImg.getHeight(), BufferedImage.TYPE_INT_RGB);
Graphics2D g2d = img.createGraphics();
g2d.drawImage(buffImg, 0, 0, null);
g2d.dispose();

If there any ideas to improve this method, please, your welcome.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...