xcode - Select branch to build in Jenkins

Question

I have several branches in my project. Is it possible to make dynamic branch selection in Jenkins's job? The idea is that Jenkins will get list of current branches and display them as possible choice parameter. Is there any way to do that? Thanks

Answer 1

I've found groovy script for this. A bit modified it. You need to select 'groovy script' instead of 'Property file'

def gitURL = "ssh://jenkins@phabricator.com/project.git"
def command = "git ls-remote -h $gitURL"

def proc = command.execute()
proc.waitFor()         

if ( proc.exitValue() != 0 ) {
   println "Error, ${proc.err.text}"
   System.exit(-1)
}     

def branches = proc.in.text.readLines().collect {
    it.replaceAll(/[a-z0-9]*refs/heads//, '') 
}   
return branches.join(",")

Idea is the same. Only now your key is ${Branch} in the job. Works well. Huge thanks @Technext for idea.