java - How to check if two streams are disjoint?

Question

I would like to compare to streams, and check if they have 1 or more elements in common (finding 1 is sufficient to stop looking for more). I want to be able to apply this to Streams containing a custom-created class.

For illustration, let's say I have a class that looks like:

public class Point {
    public final int row;
    public final int col;

    public Point(int row, int col) {
        this.row = row;
        this.col = col;
    }    

    @Override
    public boolean equals(Object obj) {
        if (obj == null) return false;
        if (obj.getClass() != this.getClass()) return false;
        final Point other = (Point) obj;
        return this.row == other.row && this.col == other.col;
    }

    @Override
    public int hashCode() {
        return Objects.hash(row, col); 
    }
}

And then I have two lovely streams that look like:

Stream<Point> streamA = Stream.of(new Point(2, 5), new Point(3, 1));
Stream<Point> streamB = Stream.of(new Point(7, 3), new Point(3, 1));

Given that these Streams have 1 Point in common (namely, Point(3, 1)), I would want the final result to be true.

The desired functionality can be pictured as:

public static boolean haveSomethingInCommon(Stream<Point> a, Stream<Point> b){
    //Code that compares a and b and returns true if they have at least 1 element in common
}

Answer 1

Without collecting the two streams independently, you can group and identify if multiple values are mapped to any key.

public static boolean haveSomethingInCommon(Stream<Coord> a, Stream<Coord> b) {
    return Stream.concat(a, b)
            .collect(Collectors.groupingBy(Function.identity()))
            .values().stream()
            .anyMatch(l -> l.size() > 1);
}

If the same stream can have the same element twice or more, you can change the code to use -

Stream.concat(a.distinct(), b.distinct())