Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
698 views
in Technique[技术] by (71.8m points)

sockets - Cannot catch SocketException

I am trying out Dart and I've been struggling with this for quite a bit now. Calling:

runServer() {
  HttpServer.bind(InternetAddress.ANY_IP_V4, 8080)
  .then((server) {
    server.listen((HttpRequest request) {
      request.response.write('Hello, World!');
      request.response.close();
    });
  });
}

Once works like a charm. And then, trying

try {
    runServer();
} on Error catch (e) {
    print("error");
} on Exception catch(f) {
    print("exception");
}

Now I'd expect that if I were to use this try-catch and start listening to the same port more than once, because I'm catching ALL exceptions and ALL errors, the program wouldn't crash. However, after running the code twice, instead of entering any try/catch clause I get:

Uncaut Error: SocketException: Failed to create server socket (OS Error: Only one usage of each socket address (protocol/network address/port) is normally permitted.

While I understand what the error is, I don't understand why doesn't it simply enter the catch Error/Exception clause?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Asynchronous errors can't be caught using try/catch (https://www.dartlang.org/docs/tutorials/futures/) at least unless you are using async/await (https://www.dartlang.org/articles/await-async/)

See also https://github.com/dart-lang/sdk/issues/24278

You can use the done future on the WebSocket object to get that error, e.g.:

import 'dart:async';
import 'dart:io';

main() async {
  // Connect to a web socket.
  WebSocket socket = await WebSocket.connect('ws://echo.websocket.org');

  // Setup listening.
  socket.listen((message) {
    print('message: $message');
  }, onError: (error) {
    print('error: $error');
  }, onDone: () {
    print('socket closed.');
  }, cancelOnError: true);

  // Add message, and then an error.
  socket.add('echo!');
  socket.addError(new Exception('error!'));

  // Wait for the socket to close.
  try {
    await socket.done;
    print('WebSocket donw');
  } catch (error) {
    print('WebScoket done with error $error');
  }
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...