Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
536 views
in Technique[技术] by (71.8m points)

javascript - Cloud Function for Firebase timeout after 60 seconds while running a bunch of Firebase queries

I am using Firebase for a group collaboration app (like Whatsapp) and I am using a Cloud Function to figure out which of the phone contacts are also using my app (again similar to Whatsapp). The Cloud Function ran fine till I started to see the following log in the Functions Log for some invocations.

Function execution took 60023 ms, finished with status: 'timeout'

I did some debugging and found that for this particular user, he has a lot of contacts on his phone's contacts book and so obviously the work required to figure out which of those contacts are using the app also increased to a point that it took more than 60 secs. Below is the code for the Cloud Function

      // contactsData is an array of contacts on the user's phone
      // Each contact can contain one more phone numbers which are
      // present in the phoneNumbers array. So, essentially, we need
      // to query over all the phone numbers in the user's contact book
      contactsData.forEach((contact) => {
        contact.phoneNumbers.forEach((phoneNumber) => {
          // Find if user with this phoneNumber is using the app
          // Check against mobileNumber and mobileNumberWithCC
          promises.push(ref.child('users').orderByChild("mobileNumber").
            equalTo(phoneNumber.number).once("value").then(usersSnapshot => {
              // usersSnapshot should contain just one entry assuming
              // that the phoneNumber will be unique to the user
              if(!usersSnapshot.exists()) {
                return null
              }
              var user = null
              usersSnapshot.forEach(userSnapshot => {
                user = userSnapshot.val()
              })
              return {
                name: contact.name,
                mobileNumber: phoneNumber.number,
                id: user.id
              }
            }))
          promises.push(ref.child('users').orderByChild("mobileNumberWithCC").
            equalTo(phoneNumber.number).once("value").then(usersSnapshot => {
              // usersSnapshot should contain just one entry assuming
              // that the phoneNumber will be unique to the user
              if(!usersSnapshot.exists()) {
                return null
              }
              var user = null
              usersSnapshot.forEach(userSnapshot => {
                user = userSnapshot.val()
              })
              return {
                name: contact.name,
                mobileNumber: phoneNumber.number,
                id: user.id
              }
            }))
        });
      });
      return Promise.all(promises)
    }).then(allContacts => {
      // allContacts is an array of nulls and contacts using the app
      // Get rid of null and any duplicate entries in the returned array
      currentContacts = arrayCompact(allContacts)

      // Create contactsObj which will the user's contacts that are using the app
      currentContacts.forEach(contact => {
        contactsObj[contact.id] = contact
      })
      // Return the currently present contacts
      return ref.child('userInfos').child(uid).child('contacts').once('value')
    }).then((contactsSnapshot) => {
      if(contactsSnapshot.exists()) {
        contactsSnapshot.forEach((contactSnapshot) => {
          previousContacts.push(contactSnapshot.val())
        })
      }
      // Update the contacts on firease asap after reading the previous contacts
      ref.child('userInfos').child(uid).child('contacts').set(contactsObj)

      // Figure out the new, deleted and renamed contacts
      newContacts = arrayDifferenceWith(currentContacts, previousContacts, 
        (obj1, obj2) => (obj1.id === obj2.id))
      deletedContacts = arrayDifferenceWith(previousContacts, currentContacts,
        (obj1, obj2) => (obj1.id === obj2.id))
      renamedContacts = arrayIntersectionWith(currentContacts, previousContacts,
        (obj1, obj2) => (obj1.id === obj2.id && obj1.name !== obj2.name))
      // Create the deletedContactsObj to store on firebase
      deletedContacts.forEach((deletedContact) => {
        deletedContactsObj[deletedContact.id] = deletedContact
      })
      // Get the deleted contacts
      return ref.child('userInfos').child(uid).child('deletedContacts').once('value')
    }).then((deletedContactsSnapshot) => {
      if(deletedContactsSnapshot.exists()) {
        deletedContactsSnapshot.forEach((deletedContactSnapshot) => {
          previouslyDeletedContacts.push(deletedContactSnapshot.val())
        })
      }
      // Contacts that were previously deleted but now added again
      restoredContacts = arrayIntersectionWith(newContacts, previouslyDeletedContacts,
        (obj1, obj2) => (obj1.id === obj2.id))
      // Removed the restored contacts from the deletedContacts
      restoredContacts.forEach((restoredContact) => {
        deletedContactsObj[restoredContact.id] = null
      })
      // Update groups using any of the deleted, new or renamed contacts
      return ContactsHelper.processContactsData(uid, deletedContacts, newContacts, renamedContacts)
    }).then(() => {
      // Set after retrieving the previously deletedContacts
      return ref.child('userInfos').child(uid).child('deletedContacts').update(deletedContactsObj)
    })

Below is some sample data

// This is a sample contactsData
[
  {
    "phoneNumbers": [
      {
        "number": "12324312321",
        "label": "home"
      },
      {
        "number": "2322412132",
        "label": "work"
      }
    ],
    "givenName": "blah5",
    "familyName": "",
    "middleName": ""
  },
  {
    "phoneNumbers": [
      {
        "number": "1231221221",
        "label": "mobile"
      }
    ],
    "givenName": "blah3",
    "familyName": "blah4",
    "middleName": ""
  },
  {
    "phoneNumbers": [
      {
        "number": "1234567890",
        "label": "mobile"
      }
    ],
    "givenName": "blah1",
    "familyName": "blah2",
    "middleName": ""
  }
]



// This is how users are stored on Firebase. This could a lot of users
  "users": {
    "id1" : {
      "countryCode" : "91",
      "id" : "id1",
      "mobileNumber" : "1231211232",
      "mobileNumberWithCC" : "911231211232",
      "name" : "Varun"
    },
    "id2" : {
      "countryCode" : "1",
      "id" : "id2",
      "mobileNumber" : "2342112133",
      "mobileNumberWithCC" : "12342112133",
      "name" : "Ashish"
    },
    "id3" : {
      "countryCode" : "1",
      "id" : "id3",
      "mobileNumber" : "123213421",
      "mobileNumberWithCC" : "1123213421",
      "name" : "Pradeep Singh"
    }
  }

In this particular case, the contactsData contained 1046 entries and for some of those entries, there were two phoneNumbers. So, let's assume there were a total of 1500 phone numbers that I need to check. I am creating queries to compare against the mobileNumber and mobileNumberWithCC for the users in the database. So, there are a total of 3000 queries that the function will make before the promise finishes and I am guessing it is taking more than 60 seconds to finish up all those queries and hence the Cloud Function timed out.

My few questions are:

  1. Is it expected for all those queries to take more than 60 secs? I was expecting it to finish much faster given that it is running within the Firebase infrastructure.
  2. Is there a way to increase the timeout limit for a function? I am currently on Blaze plan.

I will also appreciate any alternate implementation suggestions for the above function in order alleviate the problem. Thanks!

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)
Waitting for answers

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...