Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
451 views
in Technique[技术] by (71.8m points)

python - How to sort a list of lists based on length of inner list?

I want to sort a list of lists based on the length of the second item in the sublists, like this:

Input:

list = [['A', '1234', 'X'],['B', '12', 'X'],['C', '12345', 'X'],['D', '123', 'X']]

Output:

list = [['C', '12345', 'X'],['A', '1234', 'X'],['D', '123', 'X'],['B', '12', 'X']]

What i have so far is:

list = sorted(list, key=len, reverse=True)

But I'm not sure how to get it to look at length of on specific item in the lists. Thanks in advance!

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Using sort or sorted with custom key.

Ex:

data = [['A', '1234', 'X'],['B', '12', 'X'],['C', '12345', 'X'],['D', '123', 'X']]
data.sort(key=lambda x: len(x[1]), reverse=True)

or sorted

data = sorted(data, key=lambda x: len(x[1]), reverse=True)

print(data)

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...