Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
840 views
in Technique[技术] by (71.8m points)

r - Replace NA with previous value with limit

I would like to replace up to n NA values in vector with latest non-NA value.

For example, if:

a <- c(1,NA,NA,NA,NA,NA,2,NA,1,NA,NA,NA)
n <- 2

I would like to obtain:

c(1,1,1,NA,NA,NA,2,2,1,1,1,NA)

n is maximum number of NA values that can be replaced by given element).

I know na.locf() function, but I don't know how to set the limit n. Is it possible to do it?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Here's an option using na.locf and rle

library(zoo)
r <- rle(is.na(a))
a <- na.locf(a)
is.na(a) <- sequence(r$lengths) > n & rep(r$values, r$lengths)
a
# [1]  1  1  1 NA NA NA  2  2  1  1  1 NA

So here I first computed the run lengths of elements in a (including the NA entries), then replaced all NA's using na.locf and finally turned those elements back to NA's where the run lengths were greater than n and the elements were NA.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...