python - Perform partial one list items match into another with a catch

Question

I have two list :

list_1 = ['world', 'abc', 'bcd', 'ghy', 'car', 'hell', 'rock']
list_2 = ['the world is big', 'i want a car', 'puppies are best', 'you rock the world']

I would like to check if words of list_1 exists in list_2 in any shape or form and simple delete that whole sentence from list_2 and finally, print list_2

For example:

the word 'world' from list_1 should take out the sentence 'the world is big' from list_2
the word 'car' from list_2 should take out the sentence 'i want a car'

I have tried using list comprehension like this, but it sadly repeats

output = [j for i in list_1 for j in list_2 if i not in j]

Answer 1

You should consider giving meaningfull names to your variable when you can, this helps you writing your code

What you want is

• iterate over the sentences
• for each check that no word from list_1 is in it

output = [sentence for sentence in list_2
          if all(word not in sentence for word in list_1)]

print(output)  # ['puppies are best']