Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
376 views
in Technique[技术] by (71.8m points)

java - Compile error when providing interface as an arraylist type

I have an interface defined as

interface ListItem {
    public String toString();
    public String getUUID();
}

And a class (BrowseItem) implementing that interface. When I try:

ArrayList<ListItem> = (method returning ArrayList of type BrowseItem)

I get an incompatible type error (found ArrayList<BrowseItem>, require ...<ListItem>)

Am I approaching this wrong?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Java generics are not covariant.

See (among many other questions on SO):


Solutions:

  • Change the return type of the problematic method. That is, change

    List<listItem> = (method returning List of type browseItem)
    // to
    List<listItem> = (method returning List of type listItem)
    
  • Use wildcard covariance (I think that's what this is called):

    List<? extends listItem> = (method returning List of type browseItem)
    

    Be aware that you cannot add items to the list if you take this route.


N.B. it is generally good practice to declare list types as List<T> and not ArrayList<T>. The pseudocode above reflects this.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...