Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
686 views
in Technique[技术] by (71.8m points)

loops - Python - Optimisation of Perfect Number search

p = []
for x in range(1, 50000000):
    count = 0
    for y in range(1, x // 2 + 1):
        if (x % y == 0):
            count += y
    if (count == x):
        p.append(x)

This is my code to try and find all the perfect numbers that originate between 1 and 50000000. It works fine for the first 3 numbers, they are between 1 and 10000. But as it progresses it becomes extremely slow. Like maybe going through 1000 numbers every 10 seconds. Then eventually going through 10 numbers every 5 seconds.

Now is there anyway I could make this faster? I tried including some smaller things, like diving x by 2 to make sure we don't go over half (not going to be a multiple of x)

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can do a lot better. Consider the following:

1) Think of the factorization of 36 for example: 1x36, 2x18, 3x12, 4x9, 6x6. And that's it. Going further doesn't add anything new. The next factorization would be 9x4 but we already know that (4x9). This advantage gets progressively larger (compare the root of the last number you have to check against its half)

2) There are no odd perfect numbers. This is actually a conjecture (not proven yet) but they tried everything below 10^300 and didn't find any. So there are definately exactly none < 50000000. That means you can skip half the terms.

from math import ceil
p = []
for x in range(2, 50000000, 2):
    divisors = {1}
    for y in range(2, ceil(x**0.5) + 1):
        if x % y == 0:
            divisors.update({y, (x//y)})
    if sum(divisors) == x:
        print('-', x)
        p.append(x)
#- 6
#- 28
#- 496
#- 8128

This should be a lot faster but there are definately more things one can do.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...