Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
803 views
in Technique[技术] by (71.8m points)

r - For each row extract the value in the column name that match another value in the cell

I have a question which can be easily solved with a for-loop. However, since I have hundred-thousands rows in a dataframe, this would take very long computational time, and thus I am looking for a quick and smart solution.

For each row in my dataframe, I would like to paste the value of the cell whose column name matches the one from the first column (INDEX)

The dataframe looks like this

> mydata
  INDEX    1   2    3   4    5   6
1     2 18.9 9.5 22.6 4.7 16.2 7.4
2     2 18.9 9.5 22.6 4.7 16.2 7.4
3     2 18.9 9.5 22.6 4.7 16.2 7.4
4     4 18.9 9.5 22.6 4.7 16.2 7.4
5     4 18.9 9.5 22.6 4.7 16.2 7.4
6     5 18.9 9.5 22.6 4.7 16.2 7.4

Here's the code for reproducing it:

mydata <- data.frame(INDEX=c(2,2,2,4,4,5), ONE=(rep(18.9,6)), TWO=(rep(9.5,6)), 
                     THREE=(rep(22.6,6)), FOUR=(rep(4.7,6)), FIVE=(rep(16.2,6)), SIX=(rep(7.4,6)))
colnames(mydata) <- c("INDEX",1,2,3,4,5,6)

And this is the new dataframe with the newly calculated variable:

> new_mydf
  INDEX    1   2    3   4    5   6 VARIABLE
3     2 18.9 9.5 22.6 4.7 16.2 7.4      9.5
2     2 18.9 9.5 22.6 4.7 16.2 7.4      9.5
1     2 18.9 9.5 22.6 4.7 16.2 7.4      9.5
5     4 18.9 9.5 22.6 4.7 16.2 7.4      4.7
4     4 18.9 9.5 22.6 4.7 16.2 7.4      4.7
6     5 18.9 9.5 22.6 4.7 16.2 7.4     16.2

I solved it using the for-loop here below, but, as I wrote above, I am looking for a more straightforward solution (maybe using packages like dplyr, or other functions?), as the loop is to slow for my extended dataset

id = mydata$INDEX
new_mydf <- data.frame()
for (i in 1:length(id)) {
  mydata_row <- mydata[i,]
  value <- mydata_row$INDEX
  mydata_row["VARIABLE"] <- mydata_row[,names(mydata_row) == value]
  new_mydf <- rbind(mydata_row,new_mydf)
}
new_mydf <- new_mydf[ order(new_mydf[,1]), ] 
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Based on your loop, this use of apply with an anonymous function may be faster (with your mydata initial definition) :

mydata$VARIABLE<-apply(mydata, 1, function(x) { x[names(x)==x[names(x)=="INDEX"]] })

Edit : And it works even with INDEX in characters :

mydata <- data.frame(INDEX=c("B","B","B","D","D","E"), "A"=(rep(18.9,6)), "B"=(rep(9.5,6)), 
                 "C"=(rep(22.6,6)), "D"=(rep(4.7,6)), "E"=(rep(16.2,6)), "F"=(rep(7.4,6)))

mydata$VARIABLE<-apply(mydata, 1, function(x) { x[names(x)==x[names(x)=="INDEX"]] })

> mydata INDEX A B C D E F VARIABLE 1 B 18.9 9.5 22.6 4.7 16.2 7.4 9.5 2 B 18.9 9.5 22.6 4.7 16.2 7.4 9.5 3 B 18.9 9.5 22.6 4.7 16.2 7.4 9.5 4 D 18.9 9.5 22.6 4.7 16.2 7.4 4.7 5 D 18.9 9.5 22.6 4.7 16.2 7.4 4.7 6 E 18.9 9.5 22.6 4.7 16.2 7.4 16.2


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...