Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
571 views
in Technique[技术] by (71.8m points)

javascript - Why setTimeout(function, 0) is executed after next operation, but not in the moment of calling?

I run this code in JavaScript:

setTimeout(function(){console.log("1");}, 0);
console.log("2");

But output is:

2
1

Why not vice versa?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

The setTimeout() puts all the code in a queue, and then later based on the time, it executes. So you can see the list of procedures to execute as a line of queue. For the above code, you have:

  1. setTimeout
  2. console.log(2)
  3. Callback Functions, if any.
    1. console.log(1)

So, first thing that executes is, initialize the timer. Secondly, the console.log gets executed and you see 2. An interesting thing to note here is, setTimeout waits at least for 4 ms before executing its callback function.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...