Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
644 views
in Technique[技术] by (71.8m points)

c# - Populate file revision to treeview

I try to populate list of file revision to treeview. I have a list of revision file like a below.

1.17
1.17.1.1
1.17.1.2
1.17.1.2.1.1    
1.17.1.2.1.2
1.17.1.2.1.2.1.1    
1.17.1.2.1.2.1.2
1.17.1.2.1.2.1.3
1.17.1.2.1.2.1.3.1.1
1.17.1.2.1.2.1.3.1.2
1.17.1.2.1.2.1.3.2.1
1.17.1.2.1.2.1.4    
1.17.1.2.1.2.1.5
1.17.1.2.1.2.1.5.1.1
1.17.1.2.1.2.1.5.1.2
1.17.1.2.1.2.1.5.1.2.1.1
1.17.1.2.1.3
1.17.1.2.1.4
1.18
1.19

Now, I would like to populate it like a

1.17
    1.17.1.1
    1.17.1.2
        1.17.1.2.1.1    
        1.17.1.2.1.2
            1.17.1.2.1.2.1.1    
            1.17.1.2.1.2.1.2
            1.17.1.2.1.2.1.3
                1.17.1.2.1.2.1.3.1.1
                1.17.1.2.1.2.1.3.1.2
                1.17.1.2.1.2.1.3.2.1    
            1.17.1.2.1.2.1.4    
            1.17.1.2.1.2.1.5    
                1.17.1.2.1.2.1.5.1.1
                1.17.1.2.1.2.1.5.1.2    
                    1.17.1.2.1.2.1.5.1.2.1.1        
        1.17.1.2.1.3
        1.17.1.2.1.4                        
1.18
1.19

My idea is classified it by level

1.17         -> level 1
1.17.1.1     -> level 2
1.17.1.2     -> level 2
1.17.1.2.1.1 -> level 3
...

Then I use switch case to populate it to treeview

if level = 1 then parent node
else if level = 2 then child node
else if level = 3 then grandchild node
...

However, I don't know is it a right way to achieve my purpose. Is there any better way to do that?

Any help are appreciate and thanks so much

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can take advantage of the repeated pattern of the TreeNodes paths ( #.# ). Create an array of them using the RegEx. If there is only one item in the array, then the path is of the root node, otherwise string join the array except the last item (to concat the parent's name) and use the TreeView.Nodes.Find(..) function to find the parent node of each path.

? C#

private void PopulateTree(IEnumerable<string> paths)
{
    treeView1.BeginUpdate();
    treeView1.Nodes.Clear();

    foreach (var path in paths.OrderBy(x => x))
    {
        var node = new TreeNode { Name = path, Text = path };
        var arr = Regex.Matches(path, @"d+.d+")
            .Cast<Match>().Select(x => x.Value).ToArray();

        if (arr.Count() == 1)
            treeView1.Nodes.Add(node);
        else
        {
            var parentPath = string.Join(".", arr, 0, arr.Count() - 1);
            var parentNode = treeView1.Nodes.Find(parentPath, true).FirstOrDefault();

            if (parentNode != null)
                parentNode.Nodes.Add(node);
        }
    }

    treeView1.EndUpdate();
}

private void TheCaller()
{
    var revisionsList = //Get the list...

    PopulateTree(revisionsList);    
}

? VB.NET

Private Sub PopulateTree(paths As IEnumerable(Of String))
    TreeView1.BeginUpdate()
    TreeView1.Nodes.Clear()

    For Each path In paths.OrderBy(Function(x) x)
        Dim node As New TreeNode With {.Name = path, .Text = path}
        Dim arr = Regex.Matches(path, "d+.d+").
            Cast(Of Match).Select(Function(x) x.Value).ToArray()

        If arr.Count = 1 Then
            TreeView1.Nodes.Add(node)
        Else
            Dim parentPath = String.Join(".", arr, 0, arr.Count() - 1)
            Dim parentNode = TreeView1.Nodes.Find(parentPath, True).FirstOrDefault

            If parentNode IsNot Nothing Then
                parentNode.Nodes.Add(node)
            End If
        End If
    Next

    TreeView1.EndUpdate()
End Sub

Private Sub TheCaller()
    Dim revisionsList = 'Get the list...

    PopulateTree(revisionsList)
End Sub

The result is:

SOQ60904806


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...