Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
555 views
in Technique[技术] by (71.8m points)

xslt - build node-set variable from result tree fragment using <xsl:choose>

Is it possible to create a node-set variable from an rtf using xsl:choose (for use in MSXML engine)?

I have the following construct:

<xsl:choose>
    <xsl:when test="function-available('msxsl:node-set')">
        <xsl:variable name="colorList" select="msxsl:node-set($std:colorList)"/>
        <xsl:for-each select="$colorList/color">
             tr.testid<xsl:value-of select="@testid"/> {
                color:<xsl:value-of select="."/>;
            }
       </xsl:for-each>
    </xsl:when>
    <xsl:otherwise>
        <xsl:variable name="colorList" select="$std:colorList"/>
        <xsl:for-each select="$colorList/color">
             tr.testid<xsl:value-of select="@testid"/> {
                color:<xsl:value-of select="."/>;
            }
       </xsl:for-each>
    </xsl:otherwise>
</xsl:choose>

std:colorList being the tree fragment of course. The above works fine, and is OK because the code is the same for the two alternatives but is not that large.
But for larger code fragments I wonder whether it is possible to avoid duplicating code by first declaring the variable based on the rtf, and then perform the code; something like

<xsl:variable name="colorList">
    <xsl:choose>
        <xsl:when test="function-available('msxsl:node-set')">
            <xsl:copy-of select="msxsl:node-set($std:colorList)"/>
        </xsl:when>
        <xsl:otherwise>
            <xsl:copy-of select="$std:colorList"/>
        </xsl:otherwise>
    </xsl:choose>
</xsl:variable>

<xsl:for-each select="$colorList/color">
     tr.testid<xsl:value-of select="@testid"/> {
        color:<xsl:value-of select="."/>;
    }
</xsl:for-each>

But this does not work properly: MSXML complains about colorList not being a node-set, so it cannot be used in the xsl:for-each.

XSL transformation failed due to following error:
Expression must evaluate to a node-set.
-->$colorList<--/color

Note that in the working example, this error did not occur because of "copying" std:colorList into the colorList variable. Apparently it is an xsl parsing error, not a runtime one.
Should I use something else than xsl:copy-of? Or is there another way to achieve the same?

In case you wonder, std:colorList contents are as follows:

<std:colorList>
    <color testid="111">#FF0000</color>
    <color testid="999">#FFFF00</color>
</std:colorList>
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Unfortunately in XSLT 1.0, when xsl:variable has contained instructions rather than a select attribute, the result is always an RTF. So your careful attempts to convert the RTF to a node-set come to nothing, because it's converted straight back again.

I'm afraid there's no clean workaround (other than moving to XSLT 2.0, of course). I would suggest structuring the code like this:

<xsl:choose>
    <xsl:when test="function-available('msxsl:node-set')">
        <xsl:apply-templates select="msxsl:node-set($std:colorList)/color" mode="z"/>
    </xsl:when>
    <xsl:otherwise>
        <xsl:apply-templates select="$std:colorList/color" mode="z"/>
    </xsl:otherwise>
</xsl:choose>

<xsl:template match="color" mode="z">
     tr.testid<xsl:value-of select="@testid"/> {
                color:<xsl:value-of select="."/>;
            }
</xsl:template>

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...