Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
534 views
in Technique[技术] by (71.8m points)

c++ - isdigit raises a debug assertion when entering £ and ¬

The below code works for every character I type in except for or ?.

Why do I get a "debug assertion fail"?

#include <iostream>
#include <string>
#include <cctype>
using namespace std;

int main() {
    string input;
    while (1) {
        cout << "Input number: ";
        getline(cin, input);
        if (!isdigit(input[0]))
            cout << "not a digit
";
    }
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

The microsoft docs say:

The C++ compiler treats variables of type char, signed char, and unsigned char as having different types. Variables of type char are promoted to int as if they are type signed char by default, unless the /J compilation option is used. In this case they are treated as type unsigned char and are promoted to int without sign extension.

And they also say:

The behavior of isdigit and _isdigit_l is undefined if c is not EOF or in the range 0 through 0xFF, inclusive. When a debug CRT library is used and c is not one of these values, the functions raise an assertion.

So char is per default signed, which means as those two characters are not ASCII they are negative in your ANSI charset, and thus you get the assertion.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...