Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
863 views
in Technique[技术] by (71.8m points)

ios - Swift closure in array becomes nil in Objective-c

I created an objective-c method which will invoke a method via NSInvocation:

typedef void (^ScriptingEmptyBlock)();
typedef void (^ScriptingErrorBlock)(NSError *error);
- (void)scripting_execute:(NSString *)operation withParams:(nullable NSArray *)args {

    SEL selector = [self scripting_selectorForOperation:operation];
    Class class = [self class];
    NSMethodSignature *signature = [class instanceMethodSignatureForSelector:selector];
    NSInvocation *invocation = [NSInvocation invocationWithMethodSignature:signature];

    [invocation setSelector:selector];
    [invocation setTarget:self];
    for (int idx = 0; idx < args.count; idx ++) {
        id arg = args[idx];
        [invocation setArgument:&arg atIndex:idx + 2];

    }

    ScriptingEmptyBlock success = args[1];

    // Breakpoint added on next line to test for nil
    success(); // this is nil and would crash!
    // (lldb) po args.count
    // 3

    // (lldb) po success
    // Printing description of success:
    // (ScriptingEmptyBlock) success = 0x0000000000000000

    // (lldb) po args[1]
    // (Function)

    //[invocation getArgument:&success atIndex:2]; // also tried this and got nil as well
    [invocation invoke];

}

The method takes an "operation" which is translated into a selector by overriding scripting_selectorForOperation: in subclasses and then performs the invocation.

All of that works, except when the invoked method has block arguments they are nil, I added the test for nil I describe with comments, when attempting to read the closure from the array it will be nil.

Called like:

let successClosure: ScriptingEmptyBlock = {
                    print("Renamed product")
                }
let errorClosure: ScriptingErrorBlock = { error in
                    print("Failed to rename product: (error)")
                }
let params:[Any] = [ "testName", successClosure, errorClosure]
object.scripting_execute (ScriptOperation.updateProductName.rawValue, withParams: params)

Why is closure becoming nil?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

success is not nil (in fact, NSArray cannot contain nils). If you print it like NSLog(@"%@", success);, it will say (Function), not (null). And if you print its class like NSLog(@"%@", [success class]);, it will say _SwiftValue. Basically, it is a Swift value that is bridged into Objective-C.

The problem is that the object success points to is not an Objective-C block. It is a Swift closure, and Swift closures are not the same as Objective-C blocks. Trying to use invoke it as if it were an Objective-C block causes undefined behavior. po in the debugger prints it wrong probably because it is printing it assuming it were type ScriptingEmptyBlock (a block type). If you do po (id) success, it will print (Function).

As to how you can explicitly put an Objective-C block into the array from Swift, the only way I figured out to do it something like:

let params:[Any] = [ "testName",
                     successClosure as (@convention(block) () -> Void)!,
                     errorClosure as (@convention(block) (NSError) -> Void)!]
object.scripting_execute (ScriptOperation.updateProductName.rawValue,
                          withParams: params)

I am not sure why it's necessary to put the function type inside a !, but it doesn't seem to work otherwise. Maybe someone else can find a better way.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...