Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
1.6k views
in Technique[技术] by (71.8m points)

jquery - How to properly append json result to a select option

How to properly append json result to a select option,

sample json data

enter image description here

Ajax code:

$.ajax({
        url: 'sessions.php',
        type: 'post',
        datatype: 'json',
        data: { from: $('#datepicker_from').val().trim(), to: $('#datepicker_to').val().trim() },
        sucess: function(data){
            var toAppend = '';
            //if(typeof data === 'object'){
                for(var i=0;i<data.length;i++){
                    toAppend += '<option>'+data[i]['id']+'</option>';
                }
            //}
            $('#sessions').append(toAppend);
        }
    });

html code:

<p>Sessions: 
<select id="sessions"></select>

I already set to my php file

header("Content-Type: application/json");
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Use $.each to iterate through your JSON array that you receive from ajax call.

Note:- the spelling of success, you have written sucess.

 success: function(data){
            var toAppend = '';
           $.each(data,function(i,o){
           toAppend += '<option>'+o.id+'</option>';
          });

         $('#sessions').append(toAppend);
        }

You can do append to the DOM directly inside the each loop but it is always better to concatenate with string and then adding to the DOM later. This is a cheaper operation since you are accessing DOM only once in this case. This might not work in some complex scenarios though.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...