Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
2.1k views
in Technique[技术] by (71.8m points)

algorithm - Is this how rotation about a point is done?

Let's say I have a polygon with points:

(0,0)
(100,0)
(100,100)
(0,100)

Lets also let it's center be (50,50).

To rotate it would I add 50 to each component of each point, then do

x' = cos(theta)*x - sin(theta)*y
y' = sin(theta)*x + cos(theta)*y

Then subtract 50 from each component of each point?

Thanks

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Thats right, except at the start you need to subtract 50 to bring the polygon center back to 0, then at the end add 50 to bring the polygon back to its orignal position.

Actually what you are using here is the rotation matrix in 2D:

alt text


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...