Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
423 views
in Technique[技术] by (71.8m points)

java.util.scanner - Java - Scanner - Skips over my last nextLine() request

So I instantiate the Scanner scan a lot earlier but it skips right over my second scan.nextLine() after scan.nextInt(). I don't understand why it skips over it?

     System.out.println("Something: ");

        String name = scan.nextLine();

        System.out.println("Something?: ");

        int number = scan.nextInt();

        System.out.println("Something?: ");

        String insurer = scan.nextLine();

        System.out.println("Something?: ");

        String another = scan.nextLine();
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

because when you enter a number

    int number = scan.nextInt();

you enter some number and hit enter, it only accepts number and keeps new line character in buffer

so nextLine() will just see the terminator character and it will assume that it is blank String as input, to fix it add one scan.nextLine() after you process int

for example:

 System.out.println("Something?: ");

 int number = scan.nextInt();

 scan.nextLine(); // <-- 

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...