Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
2.4k views
in Technique[技术] by (71.8m points)

mongodb - Get count of "loglevel" for each "name"

For example I have following collection:

db.names.find({})

{ "_id" : ObjectId("5768d9b4bc6f464899594570"), "name" : "t1", "loglevel" : "ERROR" }

{ "_id" : ObjectId("5768d9d5bc6f464899594571"), "name" : "t1", "loglevel" : "ERROR" }

{ "_id" : ObjectId("5768d9dcbc6f464899594572"), "name" : "t1", "loglevel" : "WARNING" }

{ "_id" : ObjectId("5768d9dfbc6f464899594573"), "name" : "t1", "loglevel" : "WARNING" }

{ "_id" : ObjectId("5768d9e0bc6f464899594574"), "name" : "t1", "loglevel" : "WARNING" }

{ "_id" : ObjectId("5768d9e7bc6f464899594575"), "name" : "t1", "loglevel" : "INFO" }

{ "_id" : ObjectId("5768d9f3bc6f464899594576"), "name" : "t2", "loglevel" : "INFO" }

{ "_id" : ObjectId("5768d9f9bc6f464899594577"), "name" : "t2", "loglevel" : "ERROR" }

{ "_id" : ObjectId("5768da19bc6f464899594578"), "name" : "t2", "loglevel" : "ERROR" }

{ "_id" : ObjectId("5768da1abc6f464899594579"), "name" : "t2", "loglevel" : "ERROR" }

{ "_id" : ObjectId("5768da1bbc6f46489959457a"), "name" : "t2", "loglevel" : "ERROR" }

{ "_id" : ObjectId("5768e247bc6f46489959457b"), "name" : "t3", "loglevel" : "INFO" }

I have tried but I think it should be better solution (also else can be omitted)

db.names.aggregate(
    {$group: {
        _id: "$name",
        error: {$sum: {$cond: {if: {$eq: ['$loglevel', 'ERROR']}, then: {$sum: 1}, else: {$sum: 0}}}},
        warning: {$sum: {$cond: {if: {$eq: ['$loglevel', 'WARNING']}, then: {$sum: 1}, else: {$sum: 0}}}},
        info: {$sum: {$cond: {if: {$eq: ['$loglevel', 'INFO']}, then: {$sum: 1}, else: {$sum: 0}}}}
    }}
)
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Remove the { "$sum": 1 } and { "$sum": 0 } expressions in your if/else conditional blocks, substitute them with the values 1 and 0 (respectively for each conditional block).

The final pipeline should look like this, using the other $cond syntax which omits the if/else blocks:

db.names.aggregate([
    {
        "$group": {
            "_id": "$name",
            "error": { 
               "$sum": { 
                   "$cond": [ { "$eq": [ "$loglevel",  "ERROR" ] }, 1, 0] 
               }
           },
           "warning":{
               "$sum": { 
                   "$cond": [ { "$eq": [ "$loglevel", "WARNING" ] }, 1, 0 ]
                }
           },
           "info": { 
               "$sum": { 
                   "$cond": [ { "$eq": [ "$loglevel",  "INFO" ] }, 1, 0 ]
               }
           }
        }
    }
])

Or dynamically create the pipeline, given an array of possible statuses:

var statuses = ["ERROR", "WARNING", "INFO"],
    groupOperator = { "$group": { "_id": "$name" } };

statuses.forEach(function (status){ 
    groupOperator["$group"][status.toLowerCase()] = { 
       "$sum": { 
           "$cond": [ { "$eq": [ "$loglevel",  status ] }, 1, 0] 
       }
   }
});

db.names.aggregate([groupOperator]);

Output

/* 1 */
{
    "_id" : "t1",
    "error" : 2,
    "warning" : 3,
    "info" : 1
}

/* 2 */
{
    "_id" : "t2",
    "error" : 4,
    "warning" : 0,
    "info" : 1
}

/* 3 */
{
    "_id" : "t3",
    "error" : 0,
    "warning" : 0,
    "info" : 1
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...