Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
884 views
in Technique[技术] by (71.8m points)

parallel processing - Makefile run processes in background

I have this in my Makefile:

run:
     for x in *.bin ; do ./$$x ; done

such that it launches all executables one by one. I want to do this:

run:
     for x in *.bin ; do ./$$x &; done

so that it starts each executable and puts it in the background. I get a syntax error for the above statement when I put the ampersand.

I dont want to invoke the make as make & since this will run processes in the background but still one by one, whereas I want individual executables to run in the background, so that at any instant I have more than one executable running.

Thank you in advance.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Try to execute via a subshell:

run:
     for x in *.bin ; do (./$$x &); done

Maybe make -j is a better option. Try a Makefile that looks something like this:

BINS = $(shell echo *.bin)

.PHONY: $(BINS)
run: $(BINS)

*.bin:
    ./$@

And then execute with make -j <jobs> where <jobs> is number of simultaneous jobs to run.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

56.8k users

...