Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
558 views
in Technique[技术] by (71.8m points)

terminal - How to get the cursor position in a C program using termcap, without writing a character?

I would like to know how to get the cursor position (x, y) in my program, without writing anything on the screen neither tracking it all the time.

I found out a way to get its position with this function (I don't check the return of read, write, etc here to write a smaller code on this subject but I do it in my program):

void get_cursor_position(int *col, int *rows)
{
    int a = 0;
    int i = 0;
    char buf[4];

    write(1, "33[6n", 4); // string asking for the cursor position
    read(1, buf, 4);

    while (buf[i])
    {
        if (buf[i] >= 48 && buf[i] <= 57)
        {
            if (a == 0)
                *rows = atoi(&buf[i]) - 1;
            else
                *col = atoi(&buf[i]) - 1;
            a++;
        }
        i++;
    }
}

This function gives me the exact cursor position (*rows = y, *col = x), but it writes on the screen.

How can I get the cursor position without writing anything on the screen?
(If the cursor is on one of the printed characters, it will overwrite it.)
Should echo be toggled before and after sending the escape sequence?

This is a school project, so I only can use termcap, I can't use ncurses functions, the only allowed functions are tputs, tgoto, tgetstr, tgetnum, tgetflag.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

There are several problems:

  • canonical mode is buffered (see below)

  • the read is done on the file-descriptor for standard output (that may happen to work — sometimes — but don't count on it)

  • the read does not read enough characters to get a typical response

  • the response would have two decimal integers, separated by semicolon ;

  • the response would have a final character (which would become an issue if the read actually asked for enough characters...)

Further reading:

In canonical mode input processing, terminal input is processed in units of lines. A line is delimited by a newline character (NL), an end-of-file character (EOF), or an end-of-line (EOL) character. See Special Characters for more information on EOF and EOL. This means that a read request will not return until an entire line has been typed or a signal has been received. Also, no matter how many bytes are requested in the read() call, at most one line will be returned. It is not, however, necessary to read a whole line at once; any number of bytes, even one, may be requested in a read() without losing information.

    CSI Ps n  Device Status Report (DSR).
                Ps = 5  -> Status Report.
              Result ("OK") is CSI 0 n
                Ps = 6  -> Report Cursor Position (CPR) [row;column].
              Result is CSI r ; c R

That is, your program should be prepared to read Escape[ followed by two decimal integers (with no fixed limit on their length), and two other characters ; and R.

By the way, termcap by itself will do little for your solution. While ncurses has some relevant capabilities defined in the terminal database:

#       u9      terminal enquire string (equiv. to ANSI/ECMA-48 DA)
#       u8      terminal answerback description
#       u7      cursor position request (equiv. to VT100/ANSI/ECMA-48 DSR 6)
#       u6      cursor position report (equiv. to ANSI/ECMA-48 CPR)

few programs use those, and in any case you would find it difficult to use the cursor position report in a termcap application.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...