android - 如何防止单击按钮时对话框关闭(How to prevent a dialog from closing when a button is clicked)

Question

I have a dialog with EditText for input.

(我有一个使用EditText输入的对话框。)

When I click the "yes" button on dialog, it will validate the input and then close the dialog.

(当我单击对话框上的“是”按钮时，它将验证输入，然后关闭对话框。)

However, if the input is wrong, I want to remain in the same dialog.

(但是，如果输入错误，我希望保留在同一对话框中。)

Every time no matter what the input is, the dialog should be automatically closed when I click on the "no" button.

(每次无论输入什么，当我单击“否”按钮时，都应自动关闭对话框。)

How can I disable this?

(如何禁用此功能？)

By the way, I have used PositiveButton and NegativeButton for the button on dialog.

(顺便说一句，我在对话框上的按钮上使用了PositiveButton和NegativeButton。)

  ask by user304881 translate from so

Answer 1

EDIT: This only works on API 8+ as noted by some of the comments.

(编辑：这仅适用于API 8+，如某些注释所述。)

This is a late answer, but you can add an onShowListener to the AlertDialog where you can then override the onClickListener of the button.

(这是一个较晚的答案，但是您可以在AlertDialog中添加onShowListener，然后在其中可以覆盖按钮的onClickListener。)

final AlertDialog dialog = new AlertDialog.Builder(context)
        .setView(v)
        .setTitle(R.string.my_title)
        .setPositiveButton(android.R.string.ok, null) //Set to null. We override the onclick
        .setNegativeButton(android.R.string.cancel, null)
        .create();

dialog.setOnShowListener(new DialogInterface.OnShowListener() {

    @Override
    public void onShow(DialogInterface dialogInterface) {

        Button button = ((AlertDialog) dialog).getButton(AlertDialog.BUTTON_POSITIVE);
        button.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View view) {
                // TODO Do something

                //Dismiss once everything is OK.
                dialog.dismiss();
            }
        });
    }
});
dialog.show();