regex - 如何匹配除特定字符以外的任何非空白字符？(How to match any non white space character except a particular one?)

Question

In Perl \S matches any non-whitespace character.

(在Perl中\S匹配任何非空白字符。)

How can I match any non-whitespace character except a backslash \ ?

(我如何匹配除反斜杠\之外的任何非空白字符？)

  ask by Lazer translate from so

Answer 1

You can use a character class :

(您可以使用字符类 ：)

/[^s\]/

matches anything that is not a whitespace character nor a \ .

(匹配不是空格字符也不是\ 。)

Here's another example:

(这是另一个例子：)

[abc] means "match a , b or c ";

([abc]意思是“匹配a ， b或c ”；)

[^abc] means "match any character except a , b or c ".

([^abc]意思是“匹配除a ， b或c以外a任何字符”。)