json data coming data coming from database javascript function
(json数据 来自数据库 javascript函数的数据)
function fetch_data() {
var dataTable = $('#Acc_data').DataTable({
"bPaginate": false,
"info": false,
"processing": true,
"serverSide": true,
"order": [],
"ajax": {
url: "fetch_acc.php",
type: "POST",
"dataSrc": ""
}
});
}
HTML code
(HTML代码)
<table class="table" id="Acc_data" style="margin-left:30px;">
<thead class=" text-primary text-center">
<tr>
<th>
Account#
</th>
<th>
Status
</th>
<th>
Assigned_To
</th>
<th></th>
</tr>
</thead>
</table>
PHP code
(PHP代码)
while($row = mysqli_fetch_array($result))
{
$sub_array = array();
$sub_array[] = '<div contenteditable class="update text-center" data-id="'.$row["id"].'" data-column="Account#">' . $row["Accno"] . '</div>';
$sub_array[] = '<div contenteditable class="update text-center" data-id="'.$row["id"].'" data-column="Status">' . $row["stat"] . '</div>';
$sub_array[] ='<div contenteditable class="update text-center" data-id="'.$row["id"].'" data-column="Assigned_To">' . $row["email"] . '</div>';
$sub_array[] = '<button type="button" name="delete" class="btn btn-danger btn-xs delete" id="'.$row["id"].'"><i class="fa fa-trash" aria-hidden="true"></i></button>';
$data[] = $sub_array;
}
$output = array(
"data" => $data
);
echo json_encode($output);
this is creating the error "DataTables warning: table id=Acc_data - Invalid JSON response. For more information about this error, please see http://datatables.net/tn/1 ".
(这将导致错误“ DataTables警告:表id = Acc_data-无效的JSON响应。有关此错误的更多信息,请参见http://datatables.net/tn/1 ”。)
I have searched a lot but didn't find where I have done mistake.(我进行了很多搜索,但没有发现我做错了什么。)
Any sort of help will be appreciated.(任何帮助将不胜感激。)
Thanks in advance(提前致谢)
ask by user translate from so
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