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javascript - 在jQuery中,当它们都具有相同的名称时,如何获得单选按钮的值?(In jQuery, how do I get the value of a radio button when they all have the same name?)

Here is my code:(这是我的代码:)

<table>
   <tr>
      <td>Sales Promotion</td>
      <td><input type="radio" name="q12_3" value="1">1</td>
      <td><input type="radio" name="q12_3" value="2">2</td>
      <td><input type="radio" name="q12_3" value="3">3</td>
      <td><input type="radio" name="q12_3" value="4">4</td>
      <td><input type="radio" name="q12_3" value="5">5</td>
   </tr>
</table>
<button id="submit">submit</button>

Here is JS:(这是JS:)

$(function(){
    $("#submit").click(function(){      
        alert($('input[name=q12_3]').val());
    });
 });

Here is JSFIDDLE !(这是JSFIDDLE !)

Every time I click button it returns 1. Why?(每次我点击按钮它都会返回1.为什么?) Can anyone help me?(谁能帮我?)   ask by SPG translate from so

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1 Reply

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by (71.8m points)

In your code, jQuery just looks for the first instance of an input with name q12_3 , which in this case has a value of 1 .(在您的代码中,jQuery只查找名为q12_3的输入的第一个实例,在这种情况下,其值为1 。)

You want an input with name q12_3 that is :checked .(您想要一个名为q12_3的输入:checked 。)

 $("#submit").click(() => { const val = $('input[name=q12_3]:checked').val(); alert(val); }); 
 <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <table> <tr> <td>Sales Promotion</td> <td><input type="radio" name="q12_3" value="1">1</td> <td><input type="radio" name="q12_3" value="2">2</td> <td><input type="radio" name="q12_3" value="3">3</td> <td><input type="radio" name="q12_3" value="4">4</td> <td><input type="radio" name="q12_3" value="5">5</td> </tr> </table> <button id="submit">submit</button> 

Note that the above code is not the same as using .is(":checked") .(注意,以上代码是一样的使用.is(":checked"))

jQuery's is() function returns a boolean (true or false) and not (an) element(s).(jQuery的is()函数返回一个布尔值(true或false)而不是(a)元素。)

Because this answer keeps getting a lot of attention, I'll also include a vanilla JavaScript snippet.(因为这个答案一直受到很多关注,我还会包含一个vanilla JavaScript代码段。)

 document.querySelector("#submit").addEventListener("click", () => { const val = document.querySelector("input[name=q12_3]:checked").value; alert(val); }); 
 <table> <tr> <td>Sales Promotion</td> <td><input type="radio" name="q12_3" value="1">1</td> <td><input type="radio" name="q12_3" value="2">2</td> <td><input type="radio" name="q12_3" value="3">3</td> <td><input type="radio" name="q12_3" value="4">4</td> <td><input type="radio" name="q12_3" value="5">5</td> </tr> </table> <button id="submit">submit</button> 


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