javascript - JSLint说“缺少基数参数”(JSLint says “missing radix parameter”)

Question

I ran JSLint on this JavaScript code and it said:(我在此JavaScript代码上运行了JSLint，它说：)

Problem at line 32 character 30: Missing radix parameter.(第32行的字符30处的问题：基数参数丢失。)

This is the code in question:(这是有问题的代码：)

imageIndex = parseInt(id.substring(id.length - 1))-1;

What is wrong here?(怎么了)

  ask by Mike Vierwind translate from so

Answer 1

It always a good practice to pass radix with parseInt -(用parseInt传递基数始终是一个好习惯-)

parseInt(string, radix)

For decimal -(对于小数-)

parseInt(id.substring(id.length - 1), 10)

If the radix parameter is omitted, JavaScript assumes the following:(如果省略了radix参数，则JavaScript假定以下内容：)

• If the string begins with "0x", the radix is 16 (hexadecimal)(如果字符串以“ 0x”开头，则基数为16（十六进制）)
• If the string begins with "0", the radix is 8 (octal).(如果字符串以“ 0”开头，则基数为8（八进制）。) This feature is deprecated(不推荐使用此功能)
• If the string begins with any other value, the radix is 10 (decimal)(如果字符串以任何其他值开头，则基数为10（十进制）)

( Reference )(（ 参考 ）)