javascript - 如何在JavaScript或jQuery中过滤JSON数据？(How to filter JSON Data in JavaScript or jQuery?)

Question

How to filter JSON data using Javascript or jQuery?(如何使用Javascript或jQuery过滤JSON数据？)

This my JSON data:(这是我的JSON数据：) [{"name":"Lenovo Thinkpad 41A4298","website":"google"}, {"name":"Lenovo Thinkpad 41A2222","website":"google"}, {"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"}, {"name":"Lenovo Thinkpad 41A424448","website":"google"}, {"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"}, {"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"}, {"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"}, {"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}] JavaScript:(JavaScript的：) obj1 = JSON.parse(jsondata); now I only want name and website data which is contain website is equal to "yahoo"(现在我只想要包含网站的名称和网站数据等于“雅虎”)   ask by Me7888 translate from so

Answer 1

This is how you should do it : ( for google find)(这是你应该这样做的:(谷歌查找）)

$([ {"name":"Lenovo Thinkpad 41A4298","website":"google222"}, {"name":"Lenovo Thinkpad 41A2222","website":"google"} ]) .filter(function (i,n){ return n.website==='google'; }); Better solution : ( Salman's)(更好的解决方案:(萨尔曼）) $.grep( [{"name":"Lenovo Thinkpad 41A4298","website":"google"},{"name":"Lenovo Thinkpad 41A2222","website":"google"}], function( n, i ) { return n.website==='google'; }); http://jsbin.com/yakubixi/4/edit(http://jsbin.com/yakubixi/4/edit)