javascript - 在JavaScript中比较字符串的最佳方法？ [重复](Optimum way to compare strings in JavaScript? [duplicate])

Question

This question already has an answer here:

(这个问题在这里已有答案：)

• Is there a JavaScript strcmp()?

  (有没有JavaScript strcmp（）？)

  5 answers

  (5个答案)

I am trying to optimize a function which does binary search of strings in JavaScript.

(我正在尝试优化一个在JavaScript中对字符串进行二进制搜索的函数。)

Binary search requires you to know whether the key is == the pivot or < the pivot.

(二进制搜索要求您知道密钥是==枢轴还是<枢轴。)

But this requires two string comparisons in JavaScript, unlike in C like languages which have the strcmp() function that returns three values (-1, 0, +1) for (less than, equal, greater than).

(但这需要在JavaScript中进行两次字符串比较，这与C语言类似，后者的strcmp()函数返回三个值(-1, 0, +1) （小于，等于，大于）。)

Is there such a native function in JavaScript, that can return a ternary value so that just one comparison is required in each iteration of the binary search?

(JavaScript中是否存在这样的本机函数，它可以返回三元值，以便在二进制搜索的每次迭代中只需要进行一次比较？)

  ask by HRJ translate from so

Answer 1

You can use the localeCompare() method.

(您可以使用localeCompare()方法。)

string_a.localeCompare(string_b);

/* Expected Returns:

 0:  exact match

-1:  string_a < string_b

 1:  string_a > string_b

 */

Further Reading:

(进一步阅读：)

• MDN: String.prototype.localeCompare

  (MDN：String.prototype.localeCompare)

• Stack Overflow - Is there a JavaScript strcmp()?

  (Stack Overflow - 是否有JavaScript strcmp（）？)

• Tutorials Point: JavaScript String - localeCompare() Method

  (教程要点：JavaScript字符串 - localeCompare（）方法)