I found this which I made into this below, for 8 and 16 bit numbers in JavaScript:
const fetch = (x, o) => {
if (x >= o) {
return x
} else {
const v = (x * x) % o
return (x <= o / 2) ? v : o - v
}
}
const fetch16 = (x) => fetch(x, 65519)
const fetch8 = (x) => fetch(x, 251)
// the last number can be anything.
const build16 = (x, o) => fetch16((fetch16(x) + o) ^ 42703)
const build8 = (x, o) => fetch8((fetch8(x) + o) ^ 101)
let i = 0
let invalid = []
while (i < 255) {
let j = 0
while (j < 255) {
let x = build8(i, j)
if (x > 255) {
invalid.push([ i, j, x ])
}
j++
}
i++
}
console.log(JSON.stringify(invalid))
与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…