Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
133 views
in Technique[技术] by (71.8m points)

python - Disable sys.stdout, err, .. to print in terminal?

I have a pyqt5 GUI which I start with ./mygui.py. In myguy.py I added a class to handle exceptions via a popup window (copied from http://timlehr.com/python-exception-hooks-with-qt-message-box/). However, while the exceptions are now in the popup window, they keep being written in the terminal. How can I remove this? Here is the class from the link above, maybe something to change/add in there:

import sys
import traceback
import logging
# basic logger functionality
log = logging.getLogger(__name__)
handler = logging.StreamHandler(stream=sys.stdout)
log.addHandler(handler)

def show_exception_box(log_msg):
    """Checks if a QApplication instance is available and shows a messagebox with the exception message. 
    If unavailable (non-console application), log an additional notice.
    """
    if QtWidgets.QApplication.instance() is not None:
            errorbox = QtWidgets.QMessageBox()
            errorbox.setText("Oops. An unexpected error occured:
{0}".format(log_msg))
            errorbox.exec_()
    else:
        log.debug("No QApplication instance available.")
 
class UncaughtHook(QtCore.QObject):
    _exception_caught = QtCore.Signal(object)
 
    def __init__(self, *args, **kwargs):
        super(UncaughtHook, self).__init__(*args, **kwargs)

        # this registers the exception_hook() function as hook with the Python interpreter
        sys.excepthook = self.exception_hook

        # connect signal to execute the message box function always on main thread
        self._exception_caught.connect(show_exception_box)
 
    def exception_hook(self, exc_type, exc_value, exc_traceback):
        """Function handling uncaught exceptions.
        It is triggered each time an uncaught exception occurs. 
        """
        if issubclass(exc_type, KeyboardInterrupt):
            # ignore keyboard interrupt to support console applications
            sys.__excepthook__(exc_type, exc_value, exc_traceback)
        else:
            exc_info = (exc_type, exc_value, exc_traceback)
            log_msg = '
'.join([''.join(traceback.format_tb(exc_traceback)),
                                 '{0}: {1}'.format(exc_type.__name__, exc_value)])
            log.critical("Uncaught exception:
 {0}".format(log_msg), exc_info=exc_info)

            # trigger message box show
            self._exception_caught.emit(log_msg)
question from:https://stackoverflow.com/questions/66048450/disable-sys-stdout-err-to-print-in-terminal

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

According to your logic you are using as a handler the StreamHandler that sends the log to sys.stdout (the terminal in this case), if you don't want it to be sent then use NullHandler:

log = logging.getLogger(__name__)
handler = logging.NullHandler() # StreamHandler(stream=sys.stdout)
log.addHandler(handler)

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...