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in Technique[技术] by (71.8m points)

c++ - Comparison operator overloading

Which is best practice (in this case):

bool Foo::operator==(const Foo& other) {
  return bar == other.bar;
}

// Implementation 1
bool Foo::operator!=(const Foo& other) {
  return bar != other.bar
}

// Implementation 2
bool Foo::operator!=(const Foo& other) {
  return !(*this == other);
}

For operators like >, <, <=, >= I would go with implementation 2 when possible. However, for != I think implementation 1 is better since another method call is not made, is this correct?

question from:https://stackoverflow.com/questions/10575766/comparison-operator-overloading

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The second implementation has the notable constraint that == will always be the boolean opposite of !=. This is probably what you want, and it makes your code easier to maintain because you only have to change one implementation to keep the two in sync.


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