c# - Comparing Double.NaN with itself

Question

I am stuck trying to find out why these two operations return different values:

1. Double.NaN == Double.NaN returns false
2. Double.NaN.Equals(Double.NaN) returns true

I have the answer to the first part but not the second and not to "why are these two comparisons returning different values"

question from:https://stackoverflow.com/questions/14458890/comparing-double-nan-with-itself

Answer 1

The reason for the difference is simple, if not obvious.

If you use the equality operator ==, then you're using the IEEE test for equality.

If you're using the Equals(object) method, then you have to maintain the contract of object.Equals(object). When you implement this method (and the corresponding GetHashCode method), you have to maintain that contract, which is different from the IEEE behaviour.

If the Equals contract was not upheld, then the behaviour of hash tables would break.

var map = new Dictionary<double,string>();
map[double.NaN] = "NaN";
var s = map[double.NaN];

If !double.NaN.Equals(double.NaN), you'd never get your value out of the dictionary!

If the previous sentence does not make sense, then understand that the mechanics of hashing (used in Dictionary<T,U>, HashSet<T>, etc) use both the object.Equals(object) and object.GetHashCode() methods extensively, and rely upon guarantees of their behaviour.