Defining typescript generics with type safety

Question

Can you define generics with safe types, as you can with c#?

E.g.

public bool Foo<T>() where T : struct { /* */ }

Typescript now has generics, but can I perform a similar action?

Thanks.

question from:https://stackoverflow.com/questions/17655607/defining-typescript-generics-with-type-safety

Answer 1

Ok it seems you can do this:

Foo<T extends IBar>() { /* */ }

And that seems to make all calls require the T to implement IBar.