RAML 1.0 representation of Java Map

Question

I have RAML schema which contains "javaType": "java.util.Map<String, java.util.List<Employee>>"

I have separate schema (employee.schema) available which represent class Employee.

But as I have not used employee.schema in RAML so it is not generating class Employee and throws an Error while converting RAML to Java.

{
  "$schema": "http://json-schema.org/schema#",
  "type": "object",
  "description": "Desc",
  "properties": {
    "employeeGroups": {
      "type": "object",
      "javaType": "java.util.Map<String, java.util.List<Employee>>"
    }
  },
  "additionalProperties": false
}

Can anybody share comments how to represent "javaType": "java.util.Map<String, java.util.List<Employee>>" in RAML ?

RAML Version: 1.0

question from:https://stackoverflow.com/questions/50384943/raml-1-0-representation-of-java-map

Answer 1

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