Counting number of occurrences of a char in a string in C

Question

I have the string str

char *str = "100.10b.100.100";

I want to count the occurrences of '.' in str, preferably a one-liner. (If possible no loops)

My approach would be the standard strchr:

  int i = 0;
  char *pch=strchr(str,'.');
  while (pch!=NULL) {
    i++;
    pch=strchr(pch+1,'.');
  }

question from:https://stackoverflow.com/questions/4235519/counting-number-of-occurrences-of-a-char-in-a-string-in-c

Answer 1

Here's the way I'd do it (minimal number of variables needed):

for (i=0; s[i]; s[i]=='.' ? i++ : *s++);