What seems to be confusing you is the fact that functions that are declared to be pass-by-reference (using the &
) aren't called using actual addresses, i.e. &a
.
The simple answer is that declaring a function as pass-by-reference:
void foo(int& x);
is all we need. It's then passed by reference automatically.
You now call this function like so:
int y = 5;
foo(y);
and y
will be passed by reference.
You could also do it like this (but why would you? The mantra is: Use references when possible, pointers when needed) :
#include <iostream>
using namespace std;
class CDummy {
public:
int isitme (CDummy* param);
};
int CDummy::isitme (CDummy* param)
{
if (param == this) return true;
else return false;
}
int main () {
CDummy a;
CDummy* b = &a; // assigning address of a to b
if ( b->isitme(&a) ) // Called with &a (address of a) instead of a
cout << "yes, &a is b";
return 0;
}
Output:
yes, &a is b
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